Gold is 19 times heavier than water and copper is 9 times heavier than water. In what ratio must these metals be mixed so that the mixture may be 15 times as heavy as the other?

2 : 3

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3 : 2

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1 : 2

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2 : 1

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None

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Solution

The correct option is B
3 : 2

By the rule of allegation, we get the required ratio as $\frac{6}{4}$ =3:2

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Gold is 19 times heavier than water and copper is 9 times heavier than water. In what ratio must these metals be mixed so that the mixture may be 15 times as heavy as the other?

The correct option is B 3 : 2 By the rule of allegation, we get the required ratio as 64=3:2

The correct option is B
3 : 2

By the rule of allegation, we get the required ratio as $\frac{6}{4}$ =3:2