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Question

Gold number of potato starch is 25. Weight of potato starch required to prevent coagulation of 100 ml of gold sol by the addition of 1 ml of 10% NaCl is

A
25 g
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B
2.5 g
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C
0.005 g
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D
0.25 g
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Solution

The correct option is D 0.25 g
Amount of Starch added to 100 ml of gold sol required to prevent coagulation of 1mL of 10% NaCl sol = 0.25 g

Starch required to be added to 10 mL Gold sol to completely prevent coagulation by 1mL of 10% NaCl solution = \dfrac{25}{100} \times 10$ = 25 mg

So Gold Number = 25

So 0.25 g of Starch is required.
Option D is correct

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