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Question

Good evening mentor
what about the number of electrons housed in first shell and second shell
Are they fixed with the number 2,8 respectively
Thank you

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Solution

As per the Bohr's atomic model, Bohr named by using symbols the first orbit (main shells) which is very close to the nucleus as K, then the second orbit as L vice-versa.

First energy level (first orbit), n = 1. Symbol: K
Second energy level (second orbit), n= 2 Symbol: L
Third energy level (third orbit), n= 3 Symbol: M
Fourth energy level (fourth orbit), n= 4 Symbol: N
Fifth energy level (fifth orbit), n= 5 Symbol: O
Sixth energy level (sixth orbit), n= 6 Symbol: P

The formula for maximum occupying in a particular shell equals space 2 space straight n squared
If we use the 'n' values ( n= 1, 2, 3 ...), we can get the maximum number of electrons which occupy in a particular orbit (shell).
For the first shell (K), n=1, so the maximum electrons = 2 (1)^2 = 2 electrons
For the second shell (L), n =2, so the maximum electrons = 2 (2)^2 = 8 electrons
But it does not decide how many electrons can fill minimum.

For example Hydrogen atom, the K shell has 1 electron.
Boron atom, the K shell has 2 electrons and L shell has 3 electrons.


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