Solving a Quadratic Equation by Factorization Method
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Question
Good evening,
My doubt is
The square of a positive integer CANNOT be of the form (k is an integer):
(a) 3k + 1 (b) 4k + 2 (c) 5k + 1 (d) 5k + 4
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Solution
In the case of 3k+1 when k=1 3*1+1=4 Which is the sqare of 2 In the case of 5k+1 When k=3 5*3+1=16 Which is the sqare of 4 In the case of 5k+4 When k=1 5*1+4=9 Which is the sqare of 3 But in the case of 4k+2 For any value of k we can not get a perfect sqare So 4k+2 is the answer