wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Good evening,

My doubt is

The square of a positive integer CANNOT be of the form (k is an integer):

(a) 3k + 1 (b) 4k + 2 (c) 5k + 1 (d) 5k + 4

Open in App
Solution

In the case of 3k+1
when k=1
3*1+1=4
Which is the sqare of 2
In the case of 5k+1
When k=3
5*3+1=16
Which is the sqare of 4
In the case of 5k+4
When k=1
5*1+4=9
Which is the sqare of 3
But in the case of 4k+2
For any value of k we can not get a perfect sqare
So 4k+2 is the answer

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon