Gram molecular volume of oxygen at STP is:

3200 {c m}^{3}

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5600 {c m}^{3}

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22400 {c m}^{3}

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11200 {c m}^{3}

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Solution

The correct option is C $22400 {c m}^{3}$
Gram Molecular volume is the volume occupied by $1$ mole of molecules and $1$ mole of any gas at STP occupies $22.4$ liters $=$ $22400 c m^{3}$ volume.

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Similar questions

Q. Assertion : 20 gm of argon (atomic mass of Ar

= 40)

occupies volume of

22400 c m^{3}

at STP.
Reason : 20 gm of Neon (atomic mass of

N e = 20

) occupies a volume of

22400 c m^{3}

at STP.

Volume occupied by 1 gram of oxygen at STP is

Calculate:

a) the gram molecular mass of chlorine if 308 cm cube of it at STP weighs 0.979 grams

B) the volume of 4 gram of H2 at 4 atmospheres.

C) the mass of oxygen in 2.2 litres of carbon dioxide at STP

Q. What volume is occupied by

100.0

grams of oxygen gas

(O_{2})

at STP?

Calculate:

(a) the gram molecular mass of chlorine if $308 c m^{3}$ of it at STP weiths, 0.979 g,
(b) the volume of 4 g of $H_{2}$ at 4 atmosphere,
(c) the mass fo oxygen in 2.2 litres of $C O_{2}$ at STP.

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Gram molecular volume of oxygen at STP is:

The correct option is C 22400cm3Gram Molecular volume is the volume occupied by 1 mole of molecules and 1 mole of any gas at STP occupies 22.4 liters = 22400cm3 volume.

The correct option is C $22400 {c m}^{3}$
Gram Molecular volume is the volume occupied by $1$ mole of molecules and $1$ mole of any gas at STP occupies $22.4$ liters $=$ $22400 c m^{3}$ volume.