Question

Graph between $\log \left[\frac{x}{m}\right]$ and $\log P$ is a straight line at $45$ with intercept OA as shown.
Hence, $\left[\frac{x}{m}\right]$ at a pressure of 2 atm is

Answer 1

Equation of a straight line is given by,

$y=mx+C$

where $m=$ slope of the line.

$C=$ intercept of the y-axis.

$\therefore$ we can write for this problem,

$\log \left(\frac{x}{m}\right)=\tan \theta \times \log p+\log 2=\tan 45°\times \log 2+\log 2\theta =45°,p=2atm,$

intercept $\left(C\right)=\log 2\therefore \log \left(\frac{x}{m}\right)=0.602\therefore \frac{x}{m}=4$.