Question

Graph between $\log \left(\frac{x}{m}\right)$ and $\log P$ is a straight line at an angle ${45}^{\circ }$ with intercept on $y$-axis $0.3010$. The amount (in $g$) of the gas absorbed per $g$ of the adsorbent when pressure is $0.2atm$ is:
(Assume that the adsorption obey Freundlich isotherm)

• A. $0.4$
• B. $0.6$
• C. $0.8$
• D. $0.2$

Answer 1

The correct option is A $0.4$

According to Freundlich isotherm,
$\frac{x}{m}=K{P}^{\frac{1}{n}}\therefore \log \frac{x}{m}=\log K+\frac{1}{n}\log P$

Given: $\log K=0.3010=\log 2$
$\Rightarrow K=2$
And $\frac{1}{n}=\tan {45}^{\circ }=1$
$\Rightarrow n=1$

$\therefore \frac{x}{m}=2\times P=2\times 0.2=0.4$