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Question

Graph of binding energy per nucleon (BA) vs mass number (A) is given. x, a hypothetical nucleus with mass number A=230 splits into 2 nucleus with mass number 60 and 170. Find energy released in this fission in meV

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Solution

Loss in (BA) for A=170 is = (8-7.8) MeV=0.2 MeV

Loss in (BA) for A=60 is = (8.8-7.8) MeV=1 MeV

Energy released for A=170 is E1=0.2×170 MeV

Energy released for A=60 is E2=1×60 MeV

E=E1+E2=60+34=94.00 MeV

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