Question

Graph of binding energy per nucleon $\left(\frac{B}{A}\right)vs$ mass number (A) is given. $x$, a hypothetical nucleus with mass number A=230 splits into 2 nucleus with mass number 60 and 170. Find energy released in this fission in meV

Answer 1

Loss in $\left(\frac{B}{A}\right)$ for A=170 is = (8-7.8) MeV=0.2 MeV

Loss in $\left(\frac{B}{A}\right)$ for A=60 is = (8.8-7.8) MeV=1 MeV

Energy released for A=170 is $E_1=0.2\times 170MeV$

Energy released for A=60 is $E_2=1\times 60MeV$

$E=E_1+E_2=60+34=94.00MeV$