Graph of y=ax2+bx+c=0 is given. What conclusions can be drawn from this graph?
A
a>0
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B
b<0
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C
c<0
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D
b2−4ac>0
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Solution
The correct options are Aa>0 Bb<0 Cc<0 Db2−4ac>0 Since parabola is upward a>0 Curve is crossing x-axis at two points ⇒ roots are real ⇒b2−4ac>0 Roots are of opposite signs c/a<0⇒c<0 Also magnitude of +ve root is larger ⇒ sum of roots >0 ⇒−b/2a>0⇒b<0 Hence all the options are correct.