Question

Graph shows the acceleration of a $3kg$ particle as an applied force moves it from rest along $x-$axis. The total work done by the force on the particle by the time the particle reaches $x=6m$, is equal to

• A. $20J$
• B. $30J$
• C. $40J$
• D. $60J$

Answer 1

The correct option is D $60J$

Work done = Force. Displacement

$\Rightarrow$ Work done $=m\times \left(\text{Area of acceleration- displacement graph}\right)$

$\Rightarrow$ Work done $=3\times (\frac{1}{2}\times 2\times 4+(6-2)\times 4)=60J$