Question

Graphically represent the zeroes of the cubic polynomial: $y=x^3-3x+2$

Answer 1

Factor of $x^3-3x+2=(x-1)(x-1)(x+2)$
Plotting $(-2,0),(-1,-4),(0,-2),(1,0)$ and joining them.
Here $-1,-1,2$ are the zeroes of the cubic polynomial.
These co-ordinates are the $x$-coordinates of the three points where the graph of $x^3-3x+2$ intersects the $x$-axis.