Question

Graphically represent the zeroes of the cubic polynomial: $y=x^3+4x^2+x-6$

Answer 1

Factor of $y=x^3+4x^2+x-6=(x+2)(x-1)(x+3)$
Plotting $(1,0),(-1,-4),(2,0),(-3,0)$ and joining them.
Here $1,-2,-3$ are the zeroes of the cubic polynomial.
These co-ordinates are the $x$-coordinates of the three points where the graph of $y=x^3+4x^2+x-6$ intersects the $x$-axis.