Question

Graphically represent the zeros of the given linear polynomial: $y=x-12$

Answer 1

It is known that if the curve of $y=f\left(x\right)$ cuts the $x-$ axis at point $(p,0)$ then $p$ is said to be the zero of $y=f\left(x\right)$.

Consider $y=x-12$

Plotting $(0,-12),(12,0)$ and joining them, we get ]graph of $y=x-12$.

The graph of $x-y=12$ intersect the $x$-axis at $(12,0)$. Hence the zero of $x-12$ is $12$.