Question

Graphically represent the zeros of the given quadratic polynomial: $y=x^2-6x-16$

Answer 1

$y=x^2-6x-16$
Factor of $x^2-6x-16=(x+2)(x-8)$
Plotting $(2,-24)(8,0)(0,-16)(-2,0)(-8,96)$ and joining them.
Here, the graph cuts $x$-axis at two distinct points $A$ and $A^{\prime }$.
The $x$-coordinates of $A(8,0)$ and $A(-2,0)$ are the two zeroes of the quadratic polynomial $y=x^2-6x-16$.