Question 1
Graphically, the pair of equations
6x – 3y + 10 = 0
x – y + 9 = 0
Represents two lines which are
(A) intersecting at exactly one point.
(B) intersecting at exactly two points.
(C) coincident.
(D) parallel.

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Solution

The given equation are
6x – 3y + 10 = 0
Now, table for $2 x - y + \frac{10}{3} = 0$
$\begin{matrix} x & 0 & - \frac{5}{3} Y = 2 x + \frac{10}{3} & \frac{10}{3} & 0 P o i n t s & A & B \end{matrix} A n d t a b l e f o r 2 x - y + 9 = 0 \begin{matrix} x & 0 & - \frac{9}{2} Y = 2 x + 9 & 9 & 0 P o i n t s & C & D \end{matrix}$

Hence, the pair of equations represents two parallel lines

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Graphically, the pair of equations
6x – 3y + 10 = 0
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Represents two lines which are
(A) intersecting at exactly one point.
(B) intersecting at exactly two points.
(C) coincident.
(D) parallel.

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Question 1 Graphically, the pair of equations 6x – 3y + 10 = 0 x – y + 9 = 0 Represents two lines which are (A) intersecting at exactly one point. (B) intersecting at exactly two points. (C) coincident. (D) parallel.

The given equation are 6x – 3y + 10 = 0 Now, table for 2x−y+103=0 x0−53Y=2x+1031030PointsABAnd table for 2x−y+9=0x0−92Y=2x+990PointsCD Hence, the pair of equations represents two parallel lines

Question 1
Graphically, the pair of equations
6x – 3y + 10 = 0
x – y + 9 = 0
Represents two lines which are
(A) intersecting at exactly one point.
(B) intersecting at exactly two points.
(C) coincident.
(D) parallel.