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Universal Law of Gravitation

Gravitational...

Question

Gravitational force between two point masses $m$ and $M$ separated by a distance $r$ is $F$ . now if a point mass $3 m$ is placed very next to m, the total force on $M$ will be

A

F

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B

2 F

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C

3 F

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D

4 F

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Solution

The correct option is D $4 F$
$F = \frac{G M m}{r^{2}}$
Force on M would be,
$\frac{G M m}{r^{2}} + \frac{G M (3 m)}{r^{2}}$
$= \frac{4 G M m}{r^{2}} = 4 F$

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