Gravitational force on the surface of the moon is only $\frac{1}{6}$ as strong as gravitational force on the earth. What is the weight in newtons of a $10 k g$ object on the moon and on the earth?

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Solution

Mass of the object, $m = 10 k g$

Acceleration due to gravity at earth, $g_{e} = 9.8 m s^{- 2}$
$∴$ Weight of the object on earth, $W = m g_{e} = 10 \times 9.8 = 98 N$

Acceleration due to gravity at moon, $g_{m} = \frac{1}{6} \times 9.8 = 1.63$ $m s^{- 2}$
$∴$ Weight of the object on moon, $W = m g_{m} = 10 \times 1.63 = 16.3 N$

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Gravitational force on the surface of the moon is only 16 as strong as gravitational force on the earth. What is the weight in newtons of a 10 kg object on the moon and on the earth?

Mass of the object, m=10 kgAcceleration due to gravity at earth, ge=9.8 ms−2∴ Weight of the object on earth, W=mge=10×9.8=98 NAcceleration due to gravity at moon, gm=16×9.8=1.63 ms−2∴ Weight of the object on moon, W=mgm=10×1.63=16.3 N

Gravitational force on the surface of the moon is only $\frac{1}{6}$ as strong as gravitational force on the earth. What is the weight in newtons of a $10 k g$ object on the moon and on the earth?