Question

Gravitational potential $V$ versus distance $r$ graph is represented in figure The magnitude of gravitational field intensity is equal to

• A. $8N/kg$
• B. $4N/kg$
• C. $6N/kg$
• D. $2N/kg$

Answer 1

Answer: (A)

$8N/kg$

Perpendicular distance between the equipotential lines is $1\sin \left(30°\right)=0.5m$.

Thus, the magnitude of the field intensity is $\frac{\Delta V}{\Delta r}=\frac{4}{0.5}=8N/kg$.