You visited us 1 times! Enjoying our articles? Unlock Full Access!

Iron II Chloride

Green vitriol...

Question

Green vitriol is formed by:

F e S_{2} + H_{2} O + O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

F e S_{2} + H_{2} O + C O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e S_{2} + C O + C O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F e S_{2} + C O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $F e S_{2} + H_{2} O + O_{2}$
Green vitrdiol is $F e S O_{4} .7 H_{2} O$ . It is prepared by reaction of $F e S_{2}$ with $H_{2} O$ and $O_{2}$
$2 F e S_{2} + 2 H_{2} O + 7 H_{2} O \to 2 F e S O_{4} + 2 H_{2} S O_{4}$

Suggest Corrections

Similar questions

F e S_{2}

M :

F e S_{2}

F e S_{2} + O_{2} \to F e S O_{4} + S O_{2}

F e S_{2} + K M n O_{4} + H^{+} \to F e^{3 +} + S O_{2} + M n^{2 +} + H_{2} O

F e S_{2}

F e S_{2}

F e S_{2} + O_{2} \to F e_{2} O_{3} + S O_{2}

F e S_{2}

F e S_{2} + O_{2} \to F e^{+ 3} + S O_{2}

H_{2} S O_{4}

[F e S_{2}]

F e S_{2} + O_{2} \to F e_{2} O_{3} + S O_{2}

S O_{2} + O_{2} \to S O_{3}

S O_{3} + H_{2} O \to H_{2} S O_{4}

H_{2} S O_{4}

240 kg

F e S_{2}

Join BYJU'S Learning Program