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Multi-Electron Configurations and Orbital Diagrams

Ground state ...

Question

Ground state electron configuration for Cr is given by:

[Ar] 3s

^{2}

^{4}

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[Ar] 3s

^{2}

^{5}

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[Ar] 4s

^{2}

^{5}

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[Ar] 4s

^{2}

^{4}

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[Ar] 4s

^{1}

^{5}

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Solution

The correct option is E [Ar] 4s $^{1}$ 3d $^{5}$
Due to a more stable half-filled 3d-orbital, the ground-state electron configuration for Cr would be [ $A r]$ $4 s^{1}$ $3 d^{5}$ .

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