Ground state electronic configuration of valence shell electrons in nitrogen molecule $(N_{2})$ is written as $(S_{2 s})^{2} (S *_{2 s})^{2} (P_{2 p})^{4} (S_{2 p})^{2}$ Hence, the bond order of nitrogen molecule is:

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $3$
Bond Order = $\frac{B o n d i n g O r b i t a l e l e c t r o n s - A n t i b o n d i n g O r b i t a l e l e c t r o n s}{2}$ = $\frac{8 - 2}{2}$ = 3.

Suggest Corrections

Similar questions

Q. Valence shell electronic configuration of ion of

N_{2}

molecule is written as

(σ 2 s)^{2} (σ^{*} 2 s)^{2} (Π 2 p)^{4} (σ 2 p)^{2} (Π^{*} 2 p)^{1}

. Hence the bond order of Nitrogen molecular ion is:-

Q. The electronic configuration of nitrogen is 2, 5. How many electrons in the outer shell of the nitrogen atom are not involved in the formation of a nitrogen molecule.

Q. Nitrogen molecule, in which each nitrogen atom has ______ electrons in its valence shell and required three electrons to complete the octet.

Q. Using electron-dot diagrams which show only the outermost shell electrons, show how a molecule of nitrogen, N₂, is formed from two nitrogen atoms. What name is given to this type of bonding? (Atomic number of nitrogen is 7)

Using electron- dot diagram which show only the outermost shell electrons, show how a molecule o nitrogen, $N_{2}$ , is formed from two nitrogen atoms. What name is given to this type of bonding? (Atomic number of nitrogen is 7)

Join BYJU'S Learning Program

Ground state electronic configuration of valence shell electrons in nitrogen molecule (N2) is written as (S2s)2(S∗2s)2(P2p)4(S2p)2 Hence, the bond order of nitrogen molecule is:

The correct option is A 3Bond Order = BondingOrbitalelectrons−AntibondingOrbitalelectrons2 = 8−22 = 3.

Ground state electronic configuration of valence shell electrons in nitrogen molecule $(N_{2})$ is written as $(S_{2 s})^{2} (S *_{2 s})^{2} (P_{2 p})^{4} (S_{2 p})^{2}$ Hence, the bond order of nitrogen molecule is:

The correct option is A $3$
Bond Order = $\frac{B o n d i n g O r b i t a l e l e c t r o n s - A n t i b o n d i n g O r b i t a l e l e c t r o n s}{2}$ = $\frac{8 - 2}{2}$ = 3.