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Question

GSLV launched a rocket with a ejection speed of 200 m/s and with 20 m/s2 acceleration. Mass of the rocket is 2000 kg. What will be the rate of consumption of the fuel? (Take g=10 m/s2)

A
400 kg/s
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B
300 kg/s
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C
500 kg/s
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D
600 kg/s
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Solution

The correct option is B 300 kg/sGiven, Mass of the rocket M=2000 kg Ejection speed, v=200 m/s Acceleration of the rocket a=20 m/s2 As we know, for variable mass system with constant rate of ejection μ Mdvdt=Fext−μu Here, Fext=−Mg (downward) and relative velocity of ejection u=−v (downward) ⇒Ma=−Mg+vdMdt ⇒2000×20=−2000×10+200⋅dMdt ⇒dMdt=300 kg/s is the rate of consumption of fuel.

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