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Standard XII

Physics

More about Magnetic Dipoles

Gyromagnetic ...

Question

Gyromagnetic ratio of electron revolving in circular path ( $e -$ charge of electron, $m -$ mass of electron)

e / m

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e / 2 m

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2 m / e

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m / e

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Solution

The correct option is B $e / 2 m$
Given: charge=e, mass=m
Solution: As we know the formula gyromagnetic ratio= $\frac{L}{M}$
angular momentum(L)= $\frac{n h}{2 π}$
Magnetic moment(M)= $n \times B o h r m a g n e t o n = n \times \frac{e h}{4 π m}$
So, gyromagnetic ratio $= \frac{\frac{n h}{2 π}}{n \times \frac{e h}{4 π m}} = \frac{e}{2 m}$
Hence the correct answer is B.

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Gyromagnetic ratio of electron revolving in circular path (e− charge of electron, m− mass of electron)

The correct option is B e/2mGiven: charge=e, mass=mSolution: As we know the formula gyromagnetic ratio=LMangular momentum(L)=nh2πMagnetic moment(M)=n×Bohrmagneton=n×eh4πmSo, gyromagnetic ratio=nh2πn×eh4πm=e2mHence the correct answer is B.

Gyromagnetic ratio of electron revolving in circular path ( $e -$ charge of electron, $m -$ mass of electron)