H 2- Cl 2- 2 HCl - - H -44 kcal -Heat of formation of HCl is-A- -44 kcalB- -44 kcalC- -22 kcalD- -22 kcal

The correct option is D 22 kcalGiven reaction is, H_2 + Cl_2 → 2HCl nbsp; nbsp; Δ H = 44 kcal Heat of formation is the enthalpy change accompanying the ...

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Standard XII

Chemistry

Effective Equilibrium Constant

H 2+ Cl 2→ 2 ...

Question

$H_{2} + C l_{2} \to 2 H C l; Δ H = - 44 k c a l$ .
Heat of formation of $H C l$ is:

+44 kcal

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-44 kcal

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+22 kcal

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-22 kcal

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Solution

The correct option is D -22 kcal
Given reaction is,
$H_{2} + C l_{2} \to 2 H C l$ $Δ H = - 44 k c a l$
Heat of formation is the enthalpy change accompanying the formation of one mole of the compound from its constituent elements.
For 2 moles of $H C l, Δ H = - 44 k c a l$
For 1 mole of $H C l$ , $Δ H = \frac{- 44}{2} = - 22 k c a l$

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The heat of formation of the compound in the following reaction is $H_{2} + C l_{2} \to 2 H C l + 44 K$ .cal. Calculate heat of formation of one mole of HCl gas.

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. Heat of decomposition of

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H2+Cl2→2HCl; ΔH=−44 kcal. Heat of formation of HCl is:

The correct option is D -22 kcalGiven reaction is, H2+Cl2→2HCl ΔH=−44 kcal Heat of formation is the enthalpy change accompanying the formation of one mole of the compound from its constituent elements. For 2 moles of HCl,ΔH=−44 kcal For 1 mole of HCl, ΔH=−442=−22 kcal

$H_{2} + C l_{2} \to 2 H C l; Δ H = - 44 k c a l$ .
Heat of formation of $H C l$ is: