Question

$H_2$ evolved at STP on complete reaction of 27 g of Aluminium with excess of aqueous NaOH would be

• A. 22.4
• B. 44.8
• C. 67.2
• D. 33.6 litres

Answer 1

The correct option is D 33.6 litres

$H_{2}O+Al+NaOH\to NaAl{O}_2+\frac{3}{2}{H}_2$
$27gm$ $\frac{3}{2}\times 22.4-33.6L$