H2g- 1 2 O 2 g-H2Og- H-x H2g- 1 2 O 2 g-H2Ol- H-yHeat of vaporisation of water is-

The correct option is B x y (i) #160; #160; H _ 2 ( q ) + 1 2 O _ 2 ( g ) → H _ 2 O( g ) ; Δ H=x (ii) #160; #160; H _ 2 ( g ) + 1 2 ...

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Enthalpy

H2g+ 1 2 O 2 ...

Question

$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (g); Δ H = x$
$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); Δ H = y$
Heat of vaporisation of water is:

x + y

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x - y

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y - x

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- (x + y)

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Solution

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Similar questions

H_{2 (g)} + 1 / 2 O_{2 (g)} ⟶ {H_{2} O}_{(l)}; Δ H = - 285.77 k J / m o l e

H_{2 (g)} + 1 / 2 O_{2 (g)} ⟶ {H_{2} O}_{(l)}; Δ H = - 241.84 k J / m o l e

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l); Δ H = - 285.77 K J m o l^{- 1}

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (g); Δ H = - 241.84 K J m o l^{- 1}

2 B (s) + \frac{3}{2} O_2 (g) \to B_{2} O_{3} (s .)

Δ H = - 1273 k j

H_2 (g) + \frac{1}{2} O_2 (g) \to H_2 O (l)

Δ H = - 286 k j

H_{2} O (l) \to H_{2} O (g)

Δ H = 44 k j

2 B (s) + 3 H_{2} (g) \to B_{2} H_{6} (g)

Δ H = 365 k j

B_{2} H_{6} (g) + 3 O_{2} (g) B_{2} O_{3} (s) + 3 H_{2} O (g)

Δ H = ?

C_{2} H_{2}

C_{2} H_{4}

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 68.32 k c a l

C_{2} H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ 2 C O_{2} (g) + H_{2} O (l); Δ H = - 310.61 k c a l

C_{2} H_{4} (g) + 3 O_{2} (g) ⟶ 2 C O_{2} (g) + H_{2} O (l); Δ H = - 337.32 k c a l

2 C (s) + 2 O_{2} (g) ⟶ 2 C O_{2} (g); Δ H = - 787 k J . . . (i)

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286 k J . . . (i i)

C_{2} H_{2} (g) + \frac{5}{2} O_{2} (g) ⟶ 2 C O_{2} (g) + 3 H_{2} O (l) . . . . (i i i)

Δ H = - 1301 k J

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