Question

$H_2\left(g\right)+C{l}_2\left(g\right)=2HCl\left(g\right)$;
$\Delta H$(298K) $=-22.06$kcal. For this reaction, $\Delta U$ is equal to:

• A. $-22.06+2\times {10}^{-3}\times 298\times 2kcal$
• B. $-22.06+2\times 298kcal$
• C. $-22.06-2\times 298\times 4kcal$
• D. $-22.06kcal$

Answer 1

The correct option is D $-22.06kcal$

Enthalpy of reaction=

$\Delta H=\Delta E+n_{g}RtimesT$

$\Delta E=\Delta H-n_{g}R\times T$

$\Delta E=-22.06-0\times RT=-22.06Kcal$