Question

$H_2\left(g\right)+I_2\left(g\right)\to 2HI\left(g\right)$ the rate of disappearance of $H_2$ is $1.0\times {10}^{-4}mol{L}^{-1}{s}^{-1}$. The rate of appearance of $HI$ will be:

• A. $1.0\times {10}^{-4}mol{L}^{-1}{s}^{-1}$
• B. $2.0\times {10}^{-4}mol{L}^{-1}{s}^{-1}$
• C. $0.50\times {10}^{-4}mol{L}^{-1}{s}^{-1}$
• D. $4.0\times {10}^{-4}mol{L}^{-1}{s}^{-1}$

Answer 1

The correct option is B $2.0\times {10}^{-4}mol{L}^{-1}{s}^{-1}$

$H_2\left(g\right)+I_2\left(g\right)\to 2HI\left(g\right)$

$\frac{-d\left[H_2\right]}{dt}=+\frac{d\left[HI\right]}{dt}$

$\therefore \frac{d\left[HI\right]}{dt}=2\times \frac{d{H}_2}{dt}=2\times 1\times {10}^{-4}=2\times {10}^{-4}mol{l}^{-1}{s}^{-1}$