$H_{2} (g) + V_{2} O_{5} (s) \to V_{2} O_{3} (s) + H_{2} O (l)$
Let the coefficients for the given reaction be as follows:
$a H_{2} (g) + b V_{2} O_{5} (s) \to c V_{2} O_{3} (s) + d H_{2} O (l)$
What will be the equations for the number of atoms of each element, so that each is balanced?

a = d, b = c, 5b = 3c + d

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a = d, b = 2c, 5b = 3c + d

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a = 2d, b = c, 5b = 3c + d

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2a = 2d, 2b = 2d, 2c = d

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Solution

The correct option is A
a = d, b = c, 5b = 3c + d

$a H_{2} (g) + b V_{2} O_{5} (s) \to c V_{2} O_{3} (s) + d H_{2} O (l)$

For hydrogen number of atoms on reactant and product side will be: 2a = 2d which can be written as a = d

Similarly for vanadium: 2b = 2c which can be written as b = c

For oxygen: 5b = 3c + d

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Similar questions

H_{2} (g) + V_{2} O_{5} (s) \to V_{2} O_{3} (s) + H_{2} O (l)

Let the coefficients for the given reaction be as follows:

(A) H_{2} (g) + (B) V_{2} O_{5} (s) \to (C) V_{2} O_{3} (s) + (D) H_{2} O (l)

What will be the equations for the number of atoms for each element, so that each is balanced?

$H_{2} (g) + V_{2} O_{5} (s) \to V_{2} O_{3} (s) + H_{2} O (l)$
Let the coefficients for the given reaction be as follows:
$A H_{2} (g) + B V_{2} O_{5} (s) \to C V_{2} O_{3} (s) + D H_{2} O (l)$
What will be the equations for the number of atoms each element, so that each is balanced?

{AH}_{2} (g) + {BV}_{2} O_{5} (s) \to {CV}_{2} O_{3} (s) + {DH}_{2} O(l)

A, B, C and D are the coefficients in the reaction given above. Identify the correct relation between these coefficients so that the reaction is balanced?

H_{2} (g) + V_{2} O_{5} (s) \to V_{2} O_{3} (s) + H_{2} O (l)

Let the coefficients for the given reaction be as follows:

A H_{2} (g) + B V_{2} O_{5} (s) \to C V_{2} O_{3} (s) + D H_{2} O (l)

What will be the equations for the number of atoms of each element, so that each is balanced?

{AH}_{2} (g) + {BV}_{2} O_{5} (s) \to {CV}_{2} O_{3} (s) + {DH}_{2} O(l)

A, B, C and D are the coefficients in the reaction given above. Identify the correct relation between these coefficients so that the reaction is balanced?

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H2(g)+V2O5(s)→V2O3(s)+H2O(l) Let the coefficients for the given reaction be as follows: aH2(g)+bV2O5(s)→cV2O3(s)+dH2O(l) What will be the equations for the number of atoms of each element, so that each is balanced?

The correct option is A a = d, b = c, 5b = 3c + d aH2(g)+bV2O5(s)→cV2O3(s)+dH2O(l) For hydrogen number of atoms on reactant and product side will be: 2a = 2d which can be written as a = d Similarly for vanadium: 2b = 2c which can be written as b = c For oxygen: 5b = 3c + d

$H_{2} (g) + V_{2} O_{5} (s) \to V_{2} O_{3} (s) + H_{2} O (l)$
Let the coefficients for the given reaction be as follows:
$a H_{2} (g) + b V_{2} O_{5} (s) \to c V_{2} O_{3} (s) + d H_{2} O (l)$
What will be the equations for the number of atoms of each element, so that each is balanced?