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Question

H2 gas was adsorbed on 1 g powdered copper surface forming monolayer of molecules. On desorption, total H2 collected measured 1.36cm2 at STP. Assuming the volume of 1 molecule of H2 to be 4.472×1023cm3, the specific area of copper powder turns out to be y×102cm2. Find the value of y.

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Solution

Number of molecules of H2 in 1.36cm3 =6.023×1023×1.3622400=3.66×1019
Volume of H2 molecule =4.742×1023
43πr3=4.742×1023
r=2.245×108cm
Area of cross-section of H2 molecule =πr2=3.14×(2.245×108)2 =1.583×1015cm2
Area of molecules adsorbed =(3.66×1019)×1.583×1015cm2= Area of adsorption of Cu powder = Specific area of Cu powder
Specific area of adsorption of Cu =1.583×1015×3.66×1019=579×102cm2
So, the value of y is 579.

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