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Calcination

H2 is not wid...

Question

$H_{2}$ is not widely used as the reducing agent in metallurgic process because :

many metals react with

H_{2}

at elevated temperature forming hydrides

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there is a risk of explosion from

H_{2}

and

O_{2}

present in the air

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reducing power of

H_{2}

does not increase with temperature

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reducing power of

H_{2}

, increases with temperature

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Solution

The correct options are
A there is a risk of explosion from $H_{2}$ and $O_{2}$ present in the air
B many metals react with $H_{2}$ at elevated temperature forming hydrides
C reducing power of $H_{2}$ does not increase with temperature
$H_{2}$ is not widely used as the reducing agent in metallurgic process because metals react with $H_{2}$ at elevated temperature forming hydrides. When $H_{2}$ and $O_{2}$ present in the air are combined it will be explosive. Reducing power of $H_{2}$ does not increase with temperature, which is essential in metallurgy.

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Similar questions

H_{2} O_{2}

S n

H C l

H_{2}

S n

H_{2}

In reaction

$S O_{2}$ + $H_{2} S$ $\to$ $2 H_{2} O$ + $3 S$

the reducing agent is –

H_{2}

O_{2}

H_{2}

S O_{2}

H_{2} S

S O_{2}

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