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Decarboxylation Reaction of Alkanes

H2O2 can be p...

Question

$H_{2} O_{2}$ can be prepared by the hydrolysis of peroxydisulphuric acid $(H_{2} S_{2} O_{8})$ . $H_{2} S_{2} O_{8}$ can be prepared by anodic oxidation of $H_{2} S O_{4}$ as follows :
$2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{\oplus} + 2 e^{-}$
$H_{2} S_{2} O_{8} + 2 H_{2} O \to 2 H_{2} S O_{4} + H_{2} O_{2}$
For the production of 340 g of $H_{2} O_{2}$ (in solution), the current strength(in A) required, if it was passed for 10 hours is___________.

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Solution

$H_{2} S_{2} O_{8} +, 2 H_{2} O \to 2 H_{2} S O_{4} + H_{2} O_{2}$
$2 H_{2} S O_{4} \to H_{2} S_{2} O_{8} + 2 H^{\oplus} + 2 e^{-}$
Moles of $H_{2} O_{2} = \frac{340}{34} = 10 = M o l e s o f H_{2} S_{2} O_{8}$
2F = 1 mol $H_{2} S_{2} O_{8}$
$\Rightarrow 10 m o l H_{2} S_{2} O_{8} = 20 F$
$\Rightarrow \frac{I \times 10 \times 3600}{96500} = 20 \Rightarrow I = 53.6 A$

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