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Hydrogen Peroxide

H 2 O 2 canno...

Question

$H_{2} O_{2}$ cannot oxidise :

A

P b S

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B

{N a}_{2} S O_{3}

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C

O_{3}

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D

K I

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Solution

The correct option is C $O_{3}$
Hydrogen peroxide $H_{2} O_{2}$ cannot oxidize $O_{3}$ as it is already in its oxidised form.

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Similar questions

25 m l

H_{2} O_{2}

solution, excess of acidified solution of

K I

was added. The iodine liberated required

20 m l

0.3 N

{N a}_{2} S_{2} O_{3}

solution. The volume strength of

H_{2} O_{2}

Q. Consider the following list of reagents:
Acidified

K_{2} {C r}_{2} O_{7}

K M n O_{4}, C u {S O}_{4}, H_{2} O_{2}, {C l}_{2}, O_{2}, F e {C l}_{2}, H {N O}_{3}

{N a}_{2} S_{2} O_{3}

. The total number of reagents that can oxidise aqueous iodide to iodine is:

16

O_{2}

O_{3}

\frac{N_{A}}{2}

\frac{N_{A}}{3}

atoms respectively. Reason:

16

O_{2}

O_{3}

contains same number of atoms.

S + O_{2} \to {S O}_{2}; Δ H = - 298.2 k J

{S O}_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

{S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

The heat of formation of

H_{2} {S O}_{4}

Q. Which of the following is not oxidised by

O_{3}

?

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