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Hydrogen Peroxide

H2O2 changes ...

Question

$H_{2} O_{2}$ changes aqueous $K I$ solution to:

H I

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I_{2}

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K I_{3}

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K I O_{3}

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Solution

The correct option is A $I_{2}$
$H_{2} O_{2}$ and $K I$ undergo a redox reaction, with hydrogen peroxide acting as an oxidising agent and $K I$ as a reducing agent. In the process, iodine gas is released owing to oxidation of $K I$ .

The reaction is as follows:

$H_{2} O_{2} + 2 K I + 2 H^{+} \to I_{2} + 2 H_{2} O + 2 K^{+}$

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