$H_{2} O_{2}$ is an oxidant when it reacts with:

acidified

K_{4} [F e {(C N)}_{6}]

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alkaline

K_{3} [F e {(C N)}_{6}]

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C l_{2}

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acidified

K M n O_{4}

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Solution

The correct option is D acidified $K_{4} [F e {(C N)}_{6}]$
$C l_{2}$ and $K M n O_{4}$ are stronger oxidising agents than $H_{2} O_{2}$ .

Also, $K_{3} [F e {(C N)}_{6}]$ has iron in its highest oxidation state +3 which is not possible to oxidise further.

Therefore $H_{2} O_{2}$ acts as an oxidising agent only for $K_{4} [F e {(C N)}_{6}]$ .

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Similar questions

H_{2} O_{2}

K_{4} [F e {(C N)}_{6}]

Black (A) + H_{2} S O_{4} \to gas (B) + (C)

(B) + (C H_{3} C O O)_{2} P b \to black ppt (D)

(C) + K_{3} [F e (C N)_{6}] \to blue (E)

(C)

K M n O_{4}

(A)

(K_{4} [F e (C N)_{6}])

F e (O H)_{3}

K_{4} [F e {(C N)}_{6}]

K_{3} [F e {(C N)}_{6}]

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