$H_{2} O_{2}$ is obtained by the action of dilute $H_{2} S O_{4}$ on:

M n O_{2}

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P b O_{2}

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B a O_{2}

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S n O_{2}

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Solution

The correct option is C $B a O_{2}$
Dilute $H_{2} S O_{4}$ reacts with $B a O_{2}$ to form $H_{2} O_{2}$ and $B a S O_{4}$ .
The equation is:
$H_{2} S O_{4} + B a O_{2} \to B a S O_{4} + H_{2} O_{2}$
This is a redox reaction.
The other reactions are as follows:
A) $M n O_{2} + H_{2} S O_{4} \to H_{2} O + M n S O_{4} + 0.5 O_{2}$
B) $P b O_{2} + H_{2} S O_{4} \to H_{2} O + P b S O_{4} + 0.5 O_{2}$
D) $S n O_{2} + 2 H_{2} S O_{4} \to 2 H_{2} O + S n (S O_{4})_{2}$

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