$H_{2} O_{2}$ reduces $K_{3} [F e {(C N)}_{6}]$ in:

neutral medium.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

acidic medium.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

alkaline medium.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

non-polar solution.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B alkaline medium.
$2 K_{3} F e (C N)_{6} + 2 K O H + H_{2} O_{2} alkaline \to 2 K_{4} F e (C N)_{6} + 2 H_{2} O + O_{2}$ .

Suggest Corrections

Similar questions

H_{2} O_{2}

K_{3} [F e (C N)_{6}]

K_{3} [F e (C N)_{6}]

K_{3} [F e {(C N)}_{6}]

3.333.

K_{3} [F e {(C N)}_{6}]

F e (O H)_{3}

H C l

C l_{2}

K_{4} [F e (C N)_{6}]

K_{3} [F e (C N)_{6}]

Join BYJU'S Learning Program