Question

$H_2{O}_2$ restores the colour of old lead paintings, blackened by the action of $H_{2}S$ gas by:

• A. converting $Pb{O}_2$ to $Pb$
• B. by oxidising $PbS$ to $PbS{O}_4$
• C. converting $PbC{O}_3$ to $Pb$
• D. oxidising $PbS{O}_3$ to $PbS{O}_4$

Answer 1

The correct option is B by oxidising $PbS$ to $PbS{O}_4$

$PbO\stackrel{H_{2}S}{\to }PbS\underset{4\left(O\right)}{\overset{H_2{O}_2}{\to }}PbS{O}_4$
Litharge Black White

Option B is correct.