Molar conductances of $B a C l_{2}, H_{2} S O_{4}$ and HCl at infinite dilutions are $x_{1}, x_{2}$ and $x_{3}$ respectively. Equivalent conductance of $B a S O_{4}$ at infinite dilution will be :

Q. The constraints

- x_{1} + x_{2} \leq 1, - x_{1} + 3 x_{2} \leq 9, x_{1}, x_{2} >, 0

defines on

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H2O(g)→H(g)+OH(g):ΔH1=x1OH(g)→H(g)+O(g):ΔH2=x2Based on the above given data, determine the bond energy (BE) of O−H bond :

The correct option is A x1+x22H2O(g)→H(g)+OH(g) ΔH1=x1OH(g)→H(g)+O(g) ΔH2=x2H2O(g)+O(g)⟶2OH(g) ΔH=x1−x2 for 2OH,ΔH=x1−x2for O−H=ΔH=x1x22

$H_{2} O_{(g)} \to H_{(g)} + O H_{(g)} : Δ H_{1} = x_{1}$
${O H}_{(g)} \to H_{(g)} + O_{(g)} : Δ H_{2} = x_{2}$
Based on the above given data, determine the bond energy (BE) of $O - H$ bond :

The correct option is A $\frac{x_{1} + x_{2}}{2}$
$H_{2} O_{(g)} \to H_{(g)} + O H_{(g)} Δ H_{1} = x_{1}$
${O H}_{(g)} \to H_{(g)} + O_{(g)} Δ H_{2} = x_{2}$

$H_{2} O (g) + O (g) ⟶ 2 O H (g)$ $Δ H = x_{1} - x_{2}$
for $2 O H, Δ H = x_{1} - x_{2}$
for $O - H = Δ H = \frac{x_{1} x_{2}}{2}$