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Byju's Answer
Standard XII
Chemistry
Introduction and Degree of Hydrolysis
H 2 O+ H 3 PO...
Question
H
2
O
+
H
3
P
O
4
⇌
H
3
O
+
+
H
2
P
O
−
4
;
p
K
1
=
2.15
H
2
O
+
H
2
P
O
−
4
⇌
H
3
O
+
+
H
2
P
O
2
−
4
;
p
K
2
=
7.20
Hence, pH of
0.01
M
N
a
H
2
P
O
4
is:
A
9.35
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B
4.675
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C
2.675
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D
7.350
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Solution
The correct option is
B
4.675
H
2
O
+
H
3
P
O
4
⇌
H
3
O
+
+
H
2
P
O
−
4
;
p
K
1
=
2.15
H
2
O
+
H
2
P
O
−
4
⇌
H
3
O
+
+
H
2
P
O
2
−
4
;
p
K
2
=
7.20
Hence
p
H
of
0.01
M
N
a
H
2
P
O
4
:
p
H
=
1
/
2
(
p
K
1
+
p
K
2
)
=
2.15
+
7.20
2
=
4.675
.
Suggest Corrections
0
Similar questions
Q.
Three reactions involving
H
2
P
O
−
4
are given below:
(i)
H
3
P
O
4
+
H
2
O
→
H
3
O
+
+
H
2
P
O
−
4
(ii)
H
2
P
O
−
4
+
H
2
O
→
H
P
O
2
−
4
+
H
3
O
+
(iii)
H
2
P
O
−
4
+
O
H
−
→
H
3
P
O
4
+
O
2
−
Q.
What is the
[
H
+
]
in 1M
H
3
P
O
4
if
H
3
P
O
4
⇌
H
+
+
H
2
P
O
−
4
K
a
1
=
10
−
4
H
2
P
O
−
4
⇌
H
+
+
H
P
O
−
2
4
K
a
2
=
10
−
9
H
P
O
−
2
4
⇌
H
+
+
P
O
3
−
4
K
a
3
=
10
−
13
Q.
The total number of diprotic acids among the following is:
H
3
P
O
4
,
H
2
S
O
4
,
H
3
P
O
3
,
H
2
C
O
3
,
H
2
S
2
O
7
,
H
3
B
O
3
,
H
3
P
O
2
,
H
2
C
r
O
4
,
H
2
S
O
3
Q.
Orthophosphoric acid
(
H
3
P
O
4
)
is a weak tribasic mineral acid,
H
3
P
O
4
⇌
H
+
+
H
2
P
O
−
4
;
K
a
1
=
10
−
3
H
2
P
O
−
4
⇌
H
+
+
H
P
O
−
2
4
;
K
a
2
=
10
−
7
H
P
O
−
2
4
⇌
H
+
+
P
O
−
3
4
;
K
a
3
=
10
−
13
In a solution of
0.1
M
H
3
P
O
4
, concentration of
P
O
3
−
4
is:
Q.
Calculate
[
H
+
]
,
[
H
2
P
O
4
]
,
[
H
P
O
2
−
4
]
and
[
P
O
3
−
4
]
in a
0.01
M
solution of
H
3
P
O
4
.
Take
K
1
=
7.225
×
10
−
3
,
K
2
=
6.8
×
10
−
8
,
K
3
=
4.5
×
10
−
13
.
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