Question

$H_{2}S$ a toxic gas with rotten egg like smell is used for the qualitative analysis. If the solubility of $H_{2}S$ in water at STP is $0.195m$, calculate Henry's law constant.

Answer 1

According to Henry's law

$P=K_H\times X$

$X$= solubility of the gas in liquid

$P$= Partial pressure of the gas

At STP, $P=1atm$

$\Rightarrow 1=K_H\times 0.195$

$\Rightarrow K_H=\frac{1}{0.195}$

$=5.128$

Thus, Henry's law constant is 5.128