Question

H${}_2$SO${}_4$(aq) + Ba(OH)${}_2$(aq) $\to$
In the above reaction, the products are:
I. O${}_2$(g)
II. H${}_2$O(l)
III. BaSO${}_4$(s)

• A. I
• B. III
• C. I and II
• D. I and III
• E. II and III

Answer 1

The correct option is E II and III

In the above reaction, the products are II. $H_{2}O\left(l\right)$ and III. $BaS{O}_4\left(s\right)$.
$H_{2}S{O}_4\left(aq\right)+Ba\left(OH{)}_2\right(aq)\to BaS{O}_4(aq)+2H_{2}O(l)$
Thus, sulphuric acid reacts with barium hydroxide to form barium sulphate and water.