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Hess' Law

H2C= = CH2g+ ...

Question

$H_{2} C = = C H_{2} (g) + H_{2} (g) ⟶ H_{3} C - - C H_{3} (g)$
$T h e b o n d e n e r g y o f C - - H, C - - C, C = = C a n d H - - H a r e 414, 347, 615 a n d 435 k J m o l^{- 1} r e s p e c t i v e l y .$
If the enthalpy change of the above reaction is $x$ $k J$ , then $- x$ is

A

125

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B

100

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C

225

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D

250

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Solution

The correct option is A 125
$∵ C H_{2} = = C H_{2} (g) + H_{2} (g) ⟶ C H_{3} - - C H_{3} (g); Δ H = ?$
$∴ Δ H_{R e a c t i o n} = B o n d e n e r g y d a t a u s e d f o r f o r m a t i o n o f b o n d + B o n d e n e r g y d a t a u s e d f o r d i s s o c i a t i o n o f b o n d$
$∴ Δ H_{R e a c t i o n} = - [e_{(C - - C)} + 6 \times e_{(C - - H)}] + [e_{(C = = C)} + 4 \times e_{(C - - H)}] + e_{(H - - H)}$
$= - e_{(C - - C)} - 2 \times e_{(C - - H)} + e_{(C = = C)} + e_{(H - - H)}$
$= - 347 - 2 \times 414 + 615 + 435$
$Δ H_{R e a c t i o n} = - 125 k J$

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Similar questions

H_{2} C = C H_{2} (g) + H_{2} (g) \to H_{3} C - C H_{3} (g)

The bond energy of

C - H, C - C, C = C

H - H

are 414, 347, 615 and 435 kJ mol

^{- 1}

respectively.
If the enthalpy change of the above reaction is

x

\frac{- x}{25}

H_{2} C = C H_{2} (g) + H_{2} (g) ⟶ H_{3} C - C H_{3} (g)

The bond energy of

C - H, C - C, C = C, H - H

414, 347, 615, 435 k J m o l^{- 1}

Enthalpy change of the above reaction is:

298

K the bond energies of

C - H, C - C, C = C

H - H

bonds are respectively

414, 347, 615

435

kJ mol^{-1}, the value of enthalpy change for the reaction:

H_{2} C = C H_{2} (g) + H_{2} (g) \to H_{3} C - C H_{3} (g)

298 K

If at $298 K$ , the bond energies of $C - H, C - C, C = C$ and $H - H$ bonds are $414$ , $347$ , $615$ and $435 k J / m o l$ respectively, then the value of enthalpy change for the reaction $H_{2} C = C H_{2} (g) + H_{2} (g) \to H_{3} C - C H_{3} (g)$ at $298 K$ will be:

298 K

the bond energies of

C - H, C - C, C = C

H - H

bonds are respectively

414, 347, 615

435 k J m o l^{- 1}

, the value of enthalpy change for the reaction,

H_{2} C = C H_{2} (g) + H_{2} (g) \to H_{3} C - C H_{3} (g)

298 K

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