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Standard X

Chemistry

Volume of Gases and Number of Moles

H2O2 is used ...

Question

$H_{2} O_{2}$ is used as bleaching reagent because on dissociation it gives oxygen as follows:
$H_{2} O_{2} \to H_{2} O + \frac{1}{2} O_{2}$
If "Chachi 420" used $H_{2} O_{2}$ solution to bleach her hair and she required $2.24 L O_{2}$ gas at $1$ atm and $273 K$ . She has a $H_{2} O_{2}$ solution labeled as $^{'} 5.6 V^{'}$ then what volume of such solution must she required to bleach her hair?

200

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300

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400

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500

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Solution

The correct option is C $400$ ml
5.6 volume $H_{2} O_{2}$ means 1L of solution gives 5.6 L gas $O_{2}$
Therefore 2.24L gas $O_{2}$ would be obtained from $(\frac{1}{5.6} \times 2.24) = 0.4 L$ or 400 ml of solution.

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The correct option is C 400ml5.6 volume H2O2 means 1L of solution gives 5.6 L gas O2 Therefore 2.24L gas O2 would be obtained from (15.6×2.24)=0.4L or 400 ml of solution.

The correct option is C $400$ ml
5.6 volume $H_{2} O_{2}$ means 1L of solution gives 5.6 L gas $O_{2}$
Therefore 2.24L gas $O_{2}$ would be obtained from $(\frac{1}{5.6} \times 2.24) = 0.4 L$ or 400 ml of solution.