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Catalytic Hydrogenation

H2O2 oxidises...

Question

$H_{2} O_{2}$ oxidises acidified $K_{2} C r_{2} O_{7}$ solution to blue $C r O_{5}$ in ether.

True

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False

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Solution

The correct option is A True
$K_{2} {C r}_{2} O_{7} + H_{2} {S O}_{4} + 4 H_{2} O_{2} \to 2 {C r O}_{5} + K_{2} {S O}_{4} + 5 H_{2} O .$
${C r O}_{5}$ has butterfly structure and has two peroxy linkages. Hence $C r$ is in $+ 6$ oxidation state. In enter, it forms hexacoordinated complex with ether and get stabilized.

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