Question

$H_{2}O$ is a weaker field ligand than $N{H}_3$ and ${\Delta }_{oct}$ $\left(\right[Cr\left(N{H}_3{)}_6{]}^{3+}\right)<{\Delta }_{oct}\left(\right[Cr\left(H_{2}O{)}_6{]}^{3+}\right)$
If true 1 else 0.

• A. 0

Answer 1

The correct option is A 0
From figure it can be seen that, $H_{2}O$ is weaker ligand so splitting will be less here and ${\Delta }_{oct}$ $\left(\right[Cr\left(N{H}_3{)}_6{]}^{3+}\right)<{\Delta }_{oct}\left(\right[Cr\left(H_{2}O{)}_6{]}^{3+}\right)$.