Question

$H_{2}O$ is polar, whereas $Be{F}_2$ is not because:

• A. electronegativity of F is greater than that of O
• B. $H_{2}O$ involves H-bonding ,whereas $Be{F}_2$ is a discrete molecule
• C. $H_{2}O$ is angular and $Be{F}_2$ is linear
• D. $H_{2}O$ is linear and $Be{F}_2$ is angular.

Answer 1

The correct option is C $H_{2}O$ is angular and $Be{F}_2$ is linear

Because of linear shape, dipole moments cancel each other in $Be{F}_2(F\rightleftarrows Be\rightleftarrows F)$ and thus, it is non-polar , whereas $H_{2}O$ is V-shaped and hence, it is polar.