$H_{2} S$ and $S O_{2}$ can be distinguished by :

Litmus paper

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M n O_{4}^{-}

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P b {(C H_{3} C O O)}_{2}

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H C l

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Solution

The correct option is D $P b {(C H_{3} C O O)}_{2}$
$H_{2} S$ reacts with lead acetate to give black $P b S$ .
$P b {(C H_{3} C O O)}_{2} + H_{2} S ⟶ P b S + C H_{3} C O O H$

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H_{2} S

S O_{2}

$H_{2} S a n d S O_{2}$ can be distinguished by

H C l

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