$H_{2} S$ changes to sulphur in Frasch process by reaction:

2 H_{2} S (g) + O_{2} (g) \to 2 S (g) + 2 H_{2} O (g)

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H_{2} S (g) + S O_{3} (g) \to S O_{2} (g) + S (g) + H_{2} O (g)

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2 H_{2} S (g) + S O_{2} (g) \to 3 S (g) + 2 H_{2} O (g)

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none of these

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Solution

The correct option is C $2 H_{2} S (g) + S O_{2} (g) \to 3 S (g) + 2 H_{2} O (g)$
The Frasch process is a method to extract sulfur from underground deposits. In the Frasch process, superheated water is pumped into the sulfur deposit( $S O_{2}$ ); the sulfur melts and is extracted. The Frasch process is able to produce high purity sulfur.
$2 H_{2} S (g) + S O_{2} (g) \to 3 S (g) + 2 H_{2} O (g)$
Hence, option C is correct.

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