Question

$H_{2}S$ contains $94.11\%$ sulphur; $S{O}_2$ contains $50\%$ oxygen and $H_{2}O$ contains $11.11\%$ hydrogen. Thus :

• A. law of multiple proportions is followed.
• B. law of reciprocal proportions is followed.
• C. law of conservation of mass is followed.
• D. all of the above are followed

Answer 1

The correct option is B law of reciprocal proportions is followed.

The Law of Multiple Proportions : It was given by Dalton. When one element combines with the other element to form two or more different compounds, the mass of one elements, which combines with a constant mass of the other, bear a simple ratio to one another.
$N_{2}O,NO,N{O}_2$
The law of reciprocal proportions states that, when two different elements separately combine with a fixed mass of a third element, the proportions in which they combine with one another shall be either in the same ratio or some multiple of it. For example, sulphur and carbon both form compounds with hydrogen. In methane 12g of carbon react with 4g of hydrogen. In hydrogen sulphide, 32g of sulphur react with 2g of hydrogen (i.e. 64g of S for 4g of hydrogen). Sulphur and carbon form a compound in which the C: S ratio is 12:64 (i.e. $C{S}_2$).